电力系统自动化2017，Vol.41Issue(5)：30-38,9.DOI:10.7500/AEPS20160713007
柔性配电网的最大供电能力模型
Total Supply Capability Model for Flexible Distribution Network
摘要
Abstract
This paper proposes a total supply capability (TSC) model and the solution algorithm for flexible distribution network (FDN).Firstly,FDN is defined as a distribution network,which operates in closed loop with flexible control of power flow when multiple feeders are linked together by a flexible switching station (FSS) composed of electronic switches.Secondly,the model and the solution algorithm of TSC for FDN are proposed,the model based on a new flexible load transfer strategy.Finally,the proposed model and solution algorithm are tested through a typical FDN in different scenarios.The test result is compared with the traditional TSC model,showing that TSC will either increase or remain unchanged when a traditional grid is upgraded to FDN,the reason for which is analyzed.The advantages of FDN seen from the aspect of TSC are as follows.On one hand,the TSC is easier to achieve in the FDN since the load can flexibly be distributed in the system.In contrast,only when the load is distributed in a certain specific way,can the traditional distribution network achieve TSC.(On the other hand,the network configuration of FND is more concise than that of traditional distribution network with the same TSC.The proposed method has been applied in the argumentation of the first domestic demonstration project of multi-terminals flexible closed-loop medium-voltage distribution network.关键词
柔性配电网/最大供电能力/柔性开闭站/柔性闭环/示范工程Key words
flexible distribution network (FDN)/total supply capability (TSC)/flexible switching station (FSS)/flexible closed-loop/demonstration project引用本文复制引用
肖峻,刚发运,黄仁乐,舒彬,杨楠,余潇潇..柔性配电网的最大供电能力模型[J].电力系统自动化,2017,41(5):30-38,9.基金项目
国家高技术研究发展计划(863计划)资助项目(2015AA050102) （863计划）
国家自然科学基金资助项目(51277129).This work is supported by National High Technology Research and Development Program of China (863 Program)(No.2015AA050102) and National Natural Science Foundation of China (No.51277129). （51277129）
